How do you graph #r = 4cos(5θ)#?

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Answer 1 · 2018-03-07T15:38:40

As below

Standard form of equation is #y = a cos bx + c) + d#

#y = 4 cos (5theta)#

Amplitude # = a = 4#

Period # = (2pi) / |b| = (2pi) / 5#

Phase shift #= c / b = 0#, #color(white)(aaaaa)(0 # shift to the right)

Vertical shift # = d = 0#

graph{4 cos (5x) [-10, 10, -5, 5]}