How do you solve the inverse trig function cos^-1 (-sqrt2/2)? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties 1 Answer Nghi N ยท Hriman Mar 7, 2018 (3pi)/4 Explanation: Find arccos (- sqrt2/2). cos x = - sqrt2/2 Trig Table and unit circle give 1 solution arc: x = (3pi)/4 Answer link Related questions How do you use the properties of inverse trigonometric functions to evaluate tan(arcsin (0.31))? What is \sin ( sin^{-1} frac{sqrt{2}}{2})? How do you find the exact value of \cos(tan^{-1}sqrt{3})? How do you evaluate \sec^{-1} \sqrt{2} ? How do you find cos( cot^{-1} sqrt{3} ) without a calculator? How do you rewrite sec^2 (tan^{-1} x) in terms of x? How do you use the inverse trigonometric properties to rewrite expressions in terms of x? How do you calculate sin^-1(0.1)? How do you solve the inverse trig function sin(sin^-1 (1/3))? How do you solve the inverse trig function arcsin (sin 5pi/6)? See all questions in Inverse Trigonometric Properties Impact of this question 6161 views around the world You can reuse this answer Creative Commons License