Question

A ladybug takes of with a force of 0.012 N for a distance of 6 cm. What is the work done by the ladybug during take-off?

Answer 1

Work = Force times distance, or `W=Fxxd`

Explanation:

We first convert `6cm=0.06m`

`W=0.012Nxx0.06m=0.00072Nm=0.00072J`
(since `Nm=J`)

In scientific notation this would be:

`W=1.2*10^(-2)Nxx6*10^(-2)m=7.2*10^(-4)J`