How do you solve #-9- 2( 7x + 4) = - 1#?

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Answer 1 · 2018-03-08T03:18:27

#x=-16/14#

Let's begin by distributing #-2# to #(7x+4):#

#-9(-2*7x)+##(-2*4)=-1#

#-9-14x-8=-1#

Combine like terms on the LHS:

#-14x-17=-1#

Add #17# to both sides:

#-14x-17+17=-1+17#

#-14x+0=16#

#-14x=16#

Divide both sides by #-14#:

#(-14)/-14x=16/-14#

#x=-16/14#

Answer 2 · 2018-03-08T03:27:24

x=-8/7
You have to isolate x

#-9-2(7x+4)= -1#

#-2(7x+4)= -1+9#

#-2(7x+4)= 8#

#(-2(7x+4))/-2= 8/-2#

#7x+4= -4#

#7x=-4-4#

#x=-(8/7)#