What is the axis of symmetry for the graph of the quadratic equation #y=3x^2-12+12x#?

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Answer 1 · 2018-03-08T14:14:05

#x=-2#

For any #ax^2+bx+c#, the axis of symmetry is given by #-b/(2a)#

The parabola's equation is #y=3x^2+12x-12#

Method 1

Here, #a=3# and #b=12#, so we input:

#-12/(2(3))#

#-12/6#

#x=-2#