What is the derivative ? y= [(6-5x)/(x^2-1)]^2

1 Answer
Mauricio M. · Jim H
Mar 8, 2018

#y' = 2((6-5x)/(x^2-1)) * ((5x^2 - 12x + 5)/(x^2-1)^2)#

Explanation:

#y = ((6-5x)/(x^2-1))^2#

#y' = 2((6-5x)/(x^2-1)) * ((-5(x^2 - 1) - (6-5x)(2x))/(x^2-1)^2)#

#y' = 2((6-5x)/(x^2-1)) * ((-5x^2 + 5 - 12x+10x^2)/(x^2-1)^2)#

#y' = 2((6-5x)/(x^2-1)) * ((5x^2 - 12x + 5)/(x^2-1)^2)#

Related questions
Impact of this question
1044 views around the world
You can reuse this answer
Creative Commons License