How do you solve #(7u+9)/4 - (u-2)/3=10#?

1 Answer
Mar 8, 2018

multiply both sides by both denominators to remove the fractions, and then put the LHS together, and then solve for u. #u=5#

Explanation:

#(7u+9)/4-(u-2)/3=10#

Raise both fractions to the LCD (12)
#(21u+27)/12-(4u-8)/12=10#

Multiply both sides by 12 to eliminate the fraction
#(21u+27)-(4u-8)=120#

Put the Left Hand Side (LHS) together
#21u+27-4u+8 = 17u+35 = 120#

move the constant to the RHS, then solve for u
#17u=120-35 = 85#
#u=85/17 = 5#