How do you solve #(4 – 1)[(1 + 6) + 2]#?

2 Answers
Mar 9, 2018

27

Explanation:

You start by adding the brackets, which gives you #(4-1)((1+6)+2)=(3)(7+2)# Then, you add 7 and 2 and then multiply by 3.

Mar 9, 2018

27

Explanation:

First, you would need to solve all the things put in brackets:

#( 4 - 1 )[ ( 1 + 6 ) + 2 ]#
As i said, solve the brackets:
#= ( 3 )[ ( 7 ) + 2 ]#
And then, you solve the inside bracket first, then the outside:
#= ( 3 )[ 7 + 2 ]#
#= ( 3 )[ 9 ]#
#=27#