How do you simplify #(2 3/4 - 3/8) div2/5#?

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Answer 1 · 2018-03-09T05:00:16

#=> color(teen)(5(15/16)#

#(2(3/4) - (3/8)) / (2/5)#

#=> (2(6/8) - (3/8) ) / (2/5)# making Denominator common for the terms in the numerator.

#=> ((22/8) - (3/8)) / (2/5)#

#=> ((22 - 3) / 8) * (5/2)#

#=> (19 * 5) / (8 * 2) = 95 / 16#

#=> color(teen)(5(15/16)#

Answer 2 · 2018-03-09T05:05:23

As below.

#(2(3/4) - (3/8)) / (2/5)#

#=> (2(6/8) - (3/8) ) / (2/5)# making Denominator common for the terms in the numerator.

#=> (2(6/8 - 3/8)) / (2/5) = 2((6-3)/8) * (5/2)#

#=> = 2(3/8) * (5/2)#

#=> (19/8)(5/2) = 95 / 16 = 5(15/16)#