How do you simplify #(2 3/4 - 3/8) div2/5#? Algebra Expressions, Equations, and Functions PEMDAS 2 Answers sankarankalyanam Mar 9, 2018 #=> color(teen)(5(15/16)# Explanation: #(2(3/4) - (3/8)) / (2/5)# #=> (2(6/8) - (3/8) ) / (2/5)# making Denominator common for the terms in the numerator. #=> ((22/8) - (3/8)) / (2/5)# #=> ((22 - 3) / 8) * (5/2)# #=> (19 * 5) / (8 * 2) = 95 / 16# #=> color(teen)(5(15/16)# Answer link sankarankalyanam Mar 9, 2018 As below. Explanation: #(2(3/4) - (3/8)) / (2/5)# #=> (2(6/8) - (3/8) ) / (2/5)# making Denominator common for the terms in the numerator. #=> (2(6/8 - 3/8)) / (2/5) = 2((6-3)/8) * (5/2)# #=> = 2(3/8) * (5/2)# #=> (19/8)(5/2) = 95 / 16 = 5(15/16)# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1761 views around the world You can reuse this answer Creative Commons License