What is the slope of the tangent line of #sqrt(y-e^(x-y))= C #, where C is an arbitrary constant, at #(-2,1)#?
1 Answer
Equation of tangent is
Explanation:
As tangent is saught at the point
i.e.
Hence function is
or
As slope of tangent is the value of first derivative at the point, here
or
i.e.
Hence, slope of tangent is
and equation of tangent is
graph{(sqrt(y-e^(x-y))-sqrt(1-1/e^3))(x-(e^3+1)y+3+e^3)=0 [-11.29, 8.71, -4.52, 5.48]}