How do you solve #5( u + 6) = - 3( 3u - 6) + 4u#?

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Answer 1 · 2018-03-09T15:28:41

Distribute and then move #u# over to one side to get

#u=-1.2#

#5(u+6)=-3(3u-6)+4u#

#5u+30=-9u+18+4u#

#5u+30=-5u+18#

#10u+30=18#

#10u=-12#

#u=-1.2#

Answer 2 · 2018-03-10T00:06:20

#u=(-6)/5#

#5(u+6)=-3(3u-6)+4u#

Distribute

#(5)(u)+(5)(6)=(-3)(3u)+(-3)(-6)+4u#

#5u +30=color(green)(-9u)+18color(green)(+4u)#

#5u + 30 = -5u + 18#

Subtract #color(red)(30)# from both sides

#5u cancel(+30) cancelcolor(red)(-30) = -5u + 18 - 30 #

#5u = -5u -12#

Add #5u# on both sides

#5u + 5u = -5u + 5u - 12#

#10u = -12#

#u=(-12)/10#

#u=(-6)/5#