A spring with a spring constant of 144 N/m is compressed by a distance of 16.5 cm. How much elastic potential energy is stored in the spring?

1 Answer
Harry
Mar 10, 2018

1.96 kg * #m^2#/#s^2#

Explanation:

I'm assuming that you are asking what is the elastic potential energy stored in the spring at the position stretched by 16.5 cm...

Since you know the spring constant k, 144 N/m and the spring stretch from the equilibrium position x, is 16.5 cm, or 0.165, you find the spring's potential energy from the equation PE = #1/2#k#x^2#, which equals 1.96 Joules, or kg * #m^2#/#s^2# if you want SI units.

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