How do you solve #2^x=0.5#?

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Answer 1 · 2018-03-10T06:00:08

#x=-1#

We know that for any #a^x=b#, #log_ab=x#

Here, #a=2# and #b=0.5#. So we take:

#log_2 0.5=-1#

So #x=-1#

Answer 2 · 2018-03-10T06:00:36

The answer is #x=-1#.

Rewrite #0.5# as #1/2#, then make the exponents equal each other.

#2^x=0.5#

#2^x=1/2#

#2^x=1/2^1#

#2^x=2^-1#

#2^color(red)x=2^color(red)(-1)#

#x=-1#