How do I find y as a function of x? The constant C is a positive number. ln(y-3)=ln2x^2+lnC

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Answer 1 · 2018-03-10T07:31:47

#y=2Cx^2+3#

As #lna+lnb=ln(ab)#, we can write #ln(y-3)=ln2x^2+lnC# as

#ln(y-3)=ln(2Cx^2)#

or #y-3=2Cx^2#

or #y=2Cx^2+3#

Answer 2 · 2018-03-10T07:35:45

#y = 2x^2 xx C + 3#

#ln(y-3)=ln2x^2+lnC#

Logarithm rules:

#log a + log b = log (a xx b)#

#ln(y-3)= ln (2x^2+ xx C) #

#y - 3 = 2x^2 xx C#

#y = 2x^2 xx C + 3#