Question

What is the period of cos nx?

Answer 1

the period of the function
`cosnx`
is
`x=(2pi)/n`

Explanation:

`cosnx`
`n=1`
`cosnx=cos1x`
`cosx`
has period of `x=2pi`
`x=(2pi)/1`
`n=2`
`cosnx=cos2x`
`cos2x`
has period of `2x=2pi`
`x=(2pi)/2`
`n=3`
`cosnx=cos3x`
`cos3x`
has period of `3x=2pi`
`x=(2pi)/3`

Hence, the period of the function
`cosnx`
is
`x=(2pi)/n`