How do you simplify #sqrt(2/7) -sqrt(7/2)#?

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Answer 1 · 2018-03-10T15:38:29

#(-5sqrt14)/14#

#sqrt(2/7)-sqrt(7/2)#

#:.sqrt7/sqrt7=1# and #sqrt2/sqrt2=1#

#:.=sqrt7/sqrt7xxsqrt2/sqrt7-sqrt7/sqrt2xxsqrt2/sqrt2#

#:.sqrt7xxsqrt7=7# and #sqrt2xxsqrt2=2#

#:.=((sqrt2sqrt7))/7-((sqrt2sqrt7))/2#

#:.=(2(sqrt2sqrt7)-7(sqrt2sqrt7))/14#

#:.=(-5sqrt2sqrt7)/14#

#:.=(-5sqrt14)/14#