How do you simplify #sqrt 5(sqrt5+2)#?

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Answer 1 · 2018-03-10T18:17:54

See a solution process below:

To simplify this expression multiply each term within the parenthesis by the term outside the parenthesis:

#color(red)(sqrt(5))(sqrt(5) + 2) =>#

#color(red)(sqrt(5))sqrt(5) + (color(red)(sqrt(5)) xx 2) =>#

#5 + 2sqrt(5)#

Answer 2 · 2018-03-10T18:20:35

#5+2sqrt5#

Like we would distribute a term outside to the terms in parentheses, we would do the same with the radical. This expression will be equal to:

#(sqrt5*sqrt5)+2sqrt5#

Which is equal to:

#=(sqrt5)^2+2sqrt5#

The radical and squaring the radical will cancel out, and we get:

#5+2sqrt5#

as our final answer. Hope this helps!