Question

How to integrate this? `intcolor(white).(3x^2-x+1)/(x^3-x^2)`

Answer 1

`3lnabs(x-1)+1/x+C`

Explanation:

`int(3x^2-x+1)/(x^3-x^2)dx=int(3x^2)/(x^2(x-1))dx -int(x-1)/(x^2(x-1))dx=int(3)/((x-1))dx-int1/x^2dx=3lnabs(x-1)+1/x+C`