How much power is produced if a voltage of #6 V# is applied to a circuit with a resistance of #16 Omega#?

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Answer 1 · 2018-03-11T12:32:22

Power dissipated #P# across a resistor of resistance #R# due to application of voltage #V# is #V^2/R#

Given, #V=6,R=16#

So, #P=6^2/16=2.25# watt

Answer 2 · 2018-03-11T12:32:39

#P=2.25\ \text{W}#

# #

By putting the given values in #\ \ P=V^2/R\ \ #, we have:

#P=\frac{6^2}{16}#

#P=2.25\ \text{W}#

# #

That's it!