Question

If √2 sin x - 1 = 0 find the value of 0 < x < π (?)

Answer 1

`x = pi/4, (3pi)/4`

Explanation:

`color(white)(xxx)sqrt(2) sin x - 1 = 0`

`rArr sqrt(2) sin x = 1`

`rArr sin x = 1/(sqrt(2))`

So, For `0 lt x lt pi`;

`x` can only lie on Quad I or Quad II.

For Quad I, `x = pi/4`

For Quad II, `x = (3pi)/4`

Hence Explained.