The product of three integers is 56. The second number is twice the first number. The third number is five more than the first number. What are the three numbers?

1 Answer
Elvin Jafarli
Mar 11, 2018

x = 1.4709

Explanation:

1-st number: x
2-nd number:2x
3-rd number: x+5
Solve: x 2 x (x+5) = x* (2x^2 + 10x) = 56
2x^3 + 10x^2 = 56
2x^2(x + 5) = 56
x^2(x+5) = 28
x approximately equals to 1.4709
then you find your 2-nd and 3-rd numbers

I would suggest you to double check the question

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