How do you evaluate #2( 3x ^ { 2} ) ( 2x ^ { 2} + 3x - 5)#?

1 Answer
Youssuf E.
Mar 12, 2018

#12x^4 +18x^3-30x^2#

Explanation:

Well, the idea is that you multiply through. The easy bit is to start with #2(3x^2)#

#2(3x^2)(2x^2+3x-5)#

#=> (6x^2)(2x^2+3x-5)#

Then you multiply #(6x^2)# by every term in #(2x^2+3x-5)#

#=> 12x^4 +18x^3-30x^2#

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