How do you find the slope and y intercept for: #2x+y=-16#?

2 Answers
Mar 12, 2018

#"slope "=-2," y-intercept "=-16#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"Rearrange "2x+y=-16" into this form"#

#"subtract 2x from both sides"#

#cancel(2x)cancel(-2x)+y=-2x-16#

#rArry=-2x-16larrcolor(blue)"in slope-intercept form"#

#rArr"slope "=m=-2," y-intercept "=b=-16#

Mar 12, 2018

The slope is #-2# and the y-intercept is #-16#.

Explanation:

#2x+y=-16# is the standard form for a linear equation. Solve for #y# to get the slope-intercept form:

#y=mx+b,#

where:

#m# is the slope and #b# is the y-intercept.

Original equation:

#2x+y=-16#

Subtract #2x# from both sides of the equation.

#y=-2x-16#

#m=-2# and #b=-16#.