How do you evaluate #2\frac{1}{3]-1\frac{1}{2}#?

Question

14092 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-13T03:01:28

#5/6#

Step 1: You have to Multiply the #3# and the #2# together and then add the #1# and that would all be over #3#. Then you get

#2 1/3 = (2 xx 3 + 1)/3 = 7/3#

Step 2: You do the same thing which is #2# times #1# and then add #1# and that would be all over #2#. Then you get

#1 1/2 = (1 xx 2 + 1)/2 = 3/2#

Step 3: Combine together as

#7/3 - 3/2#

Next, you have to have a common denominator of #6#. #7/3# times #2# both top and bottom. Then #3/2# is going to be times #3# both top and bottom.

#7/3 xx 2/2 = (7 xx 2)/(3 xx 2)#

#3/2 xx 3/3 = (3 xx 3)/(2 xx 3)#

Next, multiply top and bottom fractions individually, which gets to be

#14/6 - 9/6 = (14 - 9)/6 = 5/6#

Answer 2 · 2018-03-13T03:02:22

#5/6#

First, change the mixed fractions into improper fractions by multiplying the whole number by the denominator and then adding the numerator.

#2 1/3= (2xx3+1)/3 = 7/3#

#1 1/2= (1xx2+1)/2 = 3/2#

Next, find a common denominator and then multiply the top and the bottom by the same number.

#7/3 xx 2/2 = 14/6#

#3/2 xx 3/3 = 9/6#

Subtract the numerators.

#14-9= 5#

Make sure to keep the denominator.

#5/6#