How do you subtract #(9v + 5) - ( 9v + 5)#?

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Answer 1 · 2018-03-13T11:43:17

0

Both expressions are the same. If you subtract 4 from 4, the result is zero.

Or you can remove the parentheses and process the arithmetic;
#9v+5 -9v-5=9v-9v+5-5=0#

Answer 2 · 2018-03-13T11:45:47

To subtract #(9v+5)-(9v+5#), we can expand first and then simplify like terms.

Answer: #0#

We are given this expression (#9v+5)-(9v+5)# and we are trying to find an answer to this.

First, we will expand the second bracket which is #-(9v+5)#
Remember the negative in front of the bracket represents #-1#.

Now we multiply #-1# by all the numbers in the bracket, so we multiply #-1# by #9v# which is equal to #-9v# and #-1 xx 5# which is #-5#.

#-(9v+5) = -9v-5#

Now that we have expanded the bracket, we have the expression:

# 9v+5-9v-5#

We can put like terms together and simplify as much as we can.

#9v-9v =0, and 5-5 = 0.#

#9v+5-9v-5=0#