How do you multiply #2x ^ { 2} \cdot ( 3x ^ { 3} ) ^ { 3}#?

2 Answers
Mar 13, 2018

You just need to expand

Explanation:

First, remember PEDMAS. This tells you the order in which to expand or solve equations/expressions.
Parenthesis
Exponents
Division
Multiplication
Addition
Subtraction
By using this idea, expand the power in first, which will give you
#2xxx^2((3^3xxx^(3xx3))#
#2x^2(27x^9)#
You then expand the brackets, which will give u
#2x^2xx27x^9#
#27xx2xxx^(9+2)#
#54x^11#

Mar 13, 2018

#54x^11#

Explanation:

This is all one term. Remove the bracket by cubing what is inside:

#2x^2 xx color(blue)((3x^3)^3)#

#=2x^2 xx color(blue)(27x^9)#

Now multiply as usual.

#= 54x^11" "larr# multiply the numbers and add the indices,