How do you evaluate #5k ^ { - 2} \cdot - 3k ^ { 3}#?

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Answer 1 · 2018-03-14T08:42:01

#=-15k#

Since they are like terms, simple multiplication is required:
#=5k^-2*-3k^3#
Integers get added when multiplied
#=-15k#

Answer 2 · 2018-03-14T08:42:40

#-15k#

#"using the "color(blue)"law of exponents"#

#•color(white)(x)a^mxxa^n=a^((m+n))#

#rArr5k^-2xx-3k^3#

#=(5xx-3)xxk^((-2+3))#

#=-15k#