Make 30.0 mL of H2 gas from the reaction of 6M HCL and Aluminum. How do I do the Stoichiometry for this problem?

I think the chemical equation is:

3HCl + Al -----> Al(Cl)3 + H3

1 Answer
Mar 14, 2018

24.1 mg of aluminium

Explanation:

The chemical equation is #6 HCl + 2 Al -> 2 AlCl_3 + 3 H_2#.
30 mL of #H_2# correspond to 1.34 millimoles .According to stoichiometric ratio, 3 moles of #H_2# come from 2 moles of #Al#, therefore 1.34 mmoles come from 0.89 mmoles of Aluminium, =24.1 milligrams