Two bodies are projected at angle theta and 90 minus theta to the horizontal with the same speed the ratio of their horizontal ranges are?

1 Answer
Mar 14, 2018

1:11:1

Explanation:

Formula for range of a projectile is R=(u^2 sin 2 theta)/gR=u2sin2θg where,uu is the velocity of projection and thetaθ is the angle of projection.

For,uu be the same for both the bodies,

R_1 : R_2 = sin 2theta : sin 2(90-theta)=sin 2theta: sin(180-2theta)=sin 2 theta : sin 2theta=1:1R1:R2=sin2θ:sin2(90θ)=sin2θ:sin(1802θ)=sin2θ:sin2θ=1:1 (as, sin(180-2theta)=sin 2thetasin(1802θ)=sin2θ)