How do you solve # 1/(x-2) + 3/ (x+3) = 4/(x^2 +x-6)#?
1 Answer
Mar 14, 2018
Explanation:
Note that:
#(x-2)(x+3) = x^2+x-6#
So multiplying both sides of the given equation by
#(x+3)+3(x-2) = 4#
which simplifies to:
#4x-3 = 4#
Add
#4x = 7#
Divide both sides by
#x = 7/4#
Since this value makes none of the denominators