If a current of #8 A# passing through a circuit generates #72 W# of power, what is the resistance of the circuit?

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Answer 1 · 2018-03-14T22:07:40

#1.125Omega#

#P = I^2R#

power = current^2 * resistance

this can be rearranged to give

#R = P/(I^2)#

resistance = power / (current^2)

here, current #= 8A#

#8^2# = #64#

power #= 72W#

#P/(I^2) = 72/64#

#R = 72/64Omega#

#= 9/8Omega#

#= 1.125Omega#