How do you simplify #(\frac { 2a ^ { 4} b ^ { 6} } { 4a ^ { 2} } ) ^ { 4}#?

1 Answer
Marko T.
Mar 14, 2018

Answer

Explanation:

#((2a^4b^6)/(4a^2))^4#

Since its multiplication you can manipulate the #a^4/a^2# and just get #a^2# such as the rule says #a^4/a^2=a^(4-2)#

and so you get

#((a^2b^6)/2)^4#

#=(a^(2*4)b^(6*4))/2^4#

#=(a^8b^24)/32#

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