How do you find the midpoint of #(-11/2,10/7)# and #(-7/3,3/14)#?

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Answer 1 · 2018-03-14T22:49:39

The mid point is #(x,y)=(-47/12,23/28)#

You take the mean value of each of #x and y#

Consider #x#.

The mean is #1/2(-7/3-11/2) = 1/2(-14/6-33/6) = -47/12#

Consider #y#

The mean is #1/2(10/7+3/14)=1/2(20/14+3/14) =23/28#

So the mid point is #(x,y)=(-47/12,23/28)#

Tony B