How do you convert y=x^2+18x+95 in vertex form?

2 Answers
Mar 15, 2018

y=(x+9)^2+14

Explanation:

First find the vertex using the formula
x=(-b)/"2a"

a=1
b=18
c=95

x=(-(18))/"2(1)" This simplifies to x=-18/"2" which is -9.
so x=-9

So on now that we have x we can find y.

y=x^2+18x+95
y=(-9)^2+18(-9)+95
y=14

Vertex = (-9,14) where h=-9 and k=14

We now finally enter this into vertex form which is,
y=a(x-h)^2+k

x and y in the "vertex form" are not associated with the values we found earlier.

y=1(x-(-9))^2+14
y=(x+9)^2+14

Mar 15, 2018

(x+9)^2+14

Explanation:

Firstly, you have to find the vertex point. Use the formula x_v=-b/(2a). You get (h) x_v=-9 and (k)y_v=14

Since there's an imaginary 1 in front of x, the a value is 1.
Now just plug everything into the equation y=a(x-h)^2+k