A uniform rectangular trapdoor of mass m=4.0kg is hinged at one end. It is held open, making an angle theta=60^@ to the horizontal, with a force magnitude F at the open end acting perpendicular to the trapdoor. Find the force on the trapdoor?
Issaac physics
This diagram was given as a hint. I was working based on phi=theta=60^@ (not sure if this is right). I'm not too sure what causes the force N. By taking moments about the hinge, I got F=19.62N , but this apparently is not the correct answer.
Thank you very much in advance!
Issaac physics
This diagram was given as a hint. I was working based on
Thank you very much in advance!
1 Answer
You are almost got it !! See below.
Explanation:
The trap door is
So the center of mass is at
The inclination of the door is
This acts at distance
So you have a moment relation like this:
or