How do you solve the triangle given A= 48 deg C=97 deg a=12?

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Answer 1 · 2018-03-16T09:34:08

Angle #hat A = 48^@, hat B = 35^@, hat C = 97^@#

Side #a = 12, b = 9.26, c = 16.03# units

Perimeter #P = 37.29# Units

Area #A_t = 55.15# sq units

#a = 12, hatA = 48^@, hat C = 97^@#

#hat B = 180 - 48 - 97 = 35^@#

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#12 / sin 48^@ = b / sin 35^@ = c / sin 97^@#

#b = (12 * sin 35) / sin 48 ~~ 9.26#

#c = (12 * sin 97) / sin 48 ~~ 16.03#

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Perimeter of the triangle #P = 12 + 9.26 + 16.03 = 37.29# units

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Area of the triangle #A_t = (1/2) * a * b * sin C = (1/2) * 12 * 9.26 * sin 97 = 55.15# sq units