A transverse wave is given by the equation y=y_0 sin 2pi(ft-x/lambda) The maximum particle velocity will be 4 times the wave velocity if, A. lambda =(pi y_0)/4 B.lambda =(pi y_0)/2 C.lambda =pi y_0 D.lambda =2 pi y_0 ?
1 Answer
Mar 16, 2018
Explanation:
Comparing the given equation with
amplitude of particle motion is
Now,maximum particle velocity i.e maximum velocity of S.H.M is
And,wave velocity
Given condition is
so,
or,