How do you solve #(x-1)^2=9#?

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Answer 1 · 2018-03-17T03:57:33

#x=4,-2#

We have:

#(x-1)^2=9#

Taking the square root of both sides,

#sqrt((x-1)^2)=sqrt(9)#

#x-1=+-3#

#x=+-3+1#

#x=4,-2#

Answer 2 · 2018-03-17T04:01:06

#x=4# & #x=-2#

We can start by taking the #+-# square root of both sides. We get:

#x-1=+-3#

We can now break up our equation into the following:

#x-1=3# & #x-1=-3#

We can solve the equations by adding #1# to both sides yielding:

#x=4# & #x=-2#