How do you solve the following linear system #-x + y = 2 , x + 3y =2 #?

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Answer 1 · 2018-03-17T04:03:24

#(-1,1)#

We have:

#((-x+y=2),(x+3y=2))#

We can add the two equations. See how the #x# variable cancels out, as #-x+x=0#.

#4y=4#

#y=1#

We can input this into the first equation:

#-x+1=2#

#-x=1#

#x=-1#

So the solution is #(-1,1)#.

Another cool way to solve these is to graph them. Their point of intersection is the solution to this system:

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