What is the moment of inertia of a pendulum with a mass of #3 kg# that is #9 m# from the pivot?

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Answer 1 · 2018-03-17T04:41:04

#243 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by:

#I=mr^2#

where #m# is the mass of the pendulum in kilograms, #r# is the distance of the pendulum from the pivot in meters.

Plugging in the given values, we get

#I=3 \ "kg"*(9 \ "m")^2#

#=3 \ "kg"*81 \ "m"^2#

#=243 \ "kg m"^2#