How do you simplify #(8i)(-4i)#?
2 Answers
Mar 17, 2018
Explanation:
When performing the basic mathematical functions on terms that contain
We can begin to treat this as a normal multiplication problem:
Now that we have this, we need to understand how setting
(Click here for more information regarding imaginary numbers)
In this instance, however, the
Knowing this we can write our expression as:
Mar 17, 2018
Explanation:
#color(orange)"Reminder "color(white)(x)i^2=(sqrt(-1))^2=-1#
#rArr(8i)(-4i)#
#=-32i^2=-32xx-1=32#