Question

How to solve this? `int_1^3 (x^2-16) /(x-4`

Answer 1

`int_1^3(x^2-16)/(x-4)dx=12`

Explanation:

`int_1^3(x^2-16)/(x-4)dx`

= `int_1^3((x+4)(x-4))/(x-4)dx`

= `int_1^3(x+4)dx`

= `[x^2/2+4x]_1^3`

= `[3^2/2+4*3-1^2/2-4*1]`

= `9/2+12-1/2-4`

= `12`