How do you simplify #6 + 3[(12 / 4) + 5]# using order of operations? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer SourLemonn8 Mar 17, 2018 See a detailed process below. Explanation: #6+3[(12/4)+5]# #6+36/4+15# #6+9+15# #15+15# #30# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1473 views around the world You can reuse this answer Creative Commons License