How do you solve #6( - 2- 3p ) = - 6+ 4( 1- 5p )#?

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Answer 1 · 2018-03-18T07:45:27

#p=5#

We have, #6(-2-3p)=-6+4(1-5p)#
Or, #-12-18p=-6+4-20p#
Or, #2p=12-2#
Or, #2p=10#
Thus, #p=5#

Answer 2 · 2018-03-18T07:45:56

If you multiply the numbers before the parenthesis in, then you will have an ordinary equation.

#p=5#

#6(-2-3p) = -6+4(1-5p)#

You'd get :

#-12 - 18p = -6 + 4 - 20p#

Which would be simplified as:

# 2p = 10#

Which would mean that :

#p = 5#