How do you simplify #2/(3sqrt63) #?

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Answer 1 · 2018-03-18T10:32:54

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We need to rationalise the denominator, in this case multiply both numerator and denominator by #sqrt(63) #

#=> 2/( 3sqrt(63) ) * sqrt(63) / sqrt(63)#

#=> ( 2sqrt(63) ) /( 3 * 63)#

#=>( 2 * sqrt(3*3* 7 ) ) / 189 #

#=> ( 6sqrt(7) ) / 189 #

#=> (2sqrt(7) ) / 63 #

Answer 2 · 2018-03-18T10:49:24

#(2 sqrt7)/63#

#2/(3sqrt63)#

#:.=2/(3sqrt(3*3*7))#

#:.sqrt3*sqrt3=3#

#:.=2/(3*3sqrt7)#

#:.=2/(9sqrt7)#

#:.=2/(9sqrt7)xxsqrt7/sqrt7#

#:.sqrt7xxsqrt7=7#

#:.=(2sqrt7)/(9xx7)#

#:.=(2sqrt7)/63#