Question

If the length of a `38 cm` spring increases to `64 cm` when a `4 kg` weight is hanging from it, what is the spring's constant?

Answer 1

We know.if by applying force `F` we can cause `del x` amount of increase in the length of a spring,then they are related as `F=Kdel x` (where, `K` is the spring constant)

Given, `F=4*9.8=39.2N` (as,here the weight of the object is the force which causes this extension)

and , `del x=(64-38)/100=0.26m`

so, `K=F/(del x)=39.2/0.26=150.77 Nm^-1`