How do I simplify this expression? sin^2x-cos^2x/sinx-cosx

1 Answer
Hriman
Mar 18, 2018

#sinx+cosx#

Explanation:

#(sin^2x-cos^2x)/(sinx-cosx)=#

Since the numerator has a difference of squares:
#(a^2-b^2) = (a+b)*(a-b)#

#((sinx-cosx)(sinx+cosx))/(sinx-cosx)=#

#((cancel(sinx-cosx))(sinx+cosx))/cancel(sinx-cosx)=#

#sinx+cosx#

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