Question

How do you factor the expression `w^3-3w^2-54w`?

Answer 1

`w^3-3w^2-54w = w(w-9)(w+6)`

Explanation:

Given:

`w^3-3w^2-54w`

Note that all of the terms are divisible by `w`, so we can separate that out as a factor. Then note that `54 = 9 * 6` and `9 - 6 = 3`, so we find:

`w^3-3w^2-54w = w(w^2-3w-54) = w(w-9)(w+6)`