How do you simplify #sqrt10*sqrt12#?

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Answer 1 · 2018-03-19T00:26:59

#2sqrt30#

We can rewrite #sqrt10*sqrt12# as #sqrt(10*12)=sqrt120#. Now we can factor a perfect square out of #sqrt120#. We get:

#sqrt120=sqrt4*sqrt30#

#=>2sqrt30#

There are no perfect squares in #30#, so we are done!

Answer 2 · 2018-03-19T00:28:39

#sqrt(10*12)#

#=sqrt(120)#

#=sqrt(3*4*10)#

#=sqrt(4)*sqrt(30)#

#=2sqrt(30)#

sqrt(a) * sqrt(b) = sqrt(a*b)